Lesson · Grade 11 · Chemistry
Molarity: moles of solute per litre of solution
- Grade 11
- Chemistry
- 2 min 19 s
- British Columbia
- BC11-SC-38
A labelled volumetric flask builds up step by step: 5.85 g of NaCl (the solute) is dissolved in water (the solvent) and topped up until the meniscus sits on the 250.0 mL line, while the panel works out c = n ÷ V: 0.100 mol ÷ 0.2500 L = 0.400 mol/L. The video stresses that V means litres of solution, not water added, then rearranges to n = c × V to find 0.0100 mol in a 25.0 mL sample poured from the flask.
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In one sentence
The question this lesson answers
How do we say how concentrated a solution is?
A volumetric flask is made to hold exactly 250.0 millilitres when filled to its line.
Transcript
What the lesson says
How do we say how concentrated a solution is?
A volumetric flask is made to hold exactly 250.0 millilitres when filled to its line.
Take 5.85 grams of sodium chloride, NaCl: the solute, the substance that dissolves.
Dissolve it in the flask in some water, the solvent.
Then add water until the bottom of the meniscus, the curved surface, sits on the line.
After mixing, we have 250.0 millilitres of solution, an even mix of solute and solvent.
Molarity is the moles of solute in each litre of solution.
c is the molarity, n is the moles of solute, and V is the litres of solution.
Molar mass is the mass of one mole. For NaCl it is 58.44 grams per mole, so 5.85 grams is 0.100 moles.
V is 250.0 millilitres, or 0.2500 litres.
So c is 0.100 moles divided by 0.2500 litres, which is 0.400 moles per litre.
Careful: V is the volume of the whole solution, not of the water added.
Salt in 250 millilitres of water does not make exactly 250.0 millilitres of solution, so we fill to the line.
Rearranged, the formula gives moles: n equals c times V.
How many moles are in a 25.0 millilitre sample, which is 0.0250 litres?
So n is 0.400 moles per litre times 0.0250 litres, which is 0.0100 moles.
Molarity is moles of solute per litre of solution.
Curriculum
Where this fits
- British Columbia, Grade 11
Chemistry 11, Solutions: stoichiometric calculations in aqueous solutionsBC11-SC-38
Previous: Writing Dissociation EquationsNext: Dilution: More Solvent, Same Moles of Solute
The outcomes and strands follow the British Columbia curriculum.
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