Lesson · Grade 8 · Mathematics
Why the Pythagorean theorem works: a rearrangement proof
- Grade 8
- Mathematics
- 2 min 9 s
- British Columbia
- BC8-MA-31
Four copies of a right triangle with legs 3 cm and 4 cm fit into the corners of a 7 cm square and leave a tilted square gap of area c², which works out to 49 − 24 = 25 cm². Sliding three triangles without turning them changes the gap into two squares, a² = 9 and b² = 16, and because the big square and the triangles did not change, a² + b² = c² (9 + 16 = 25, so c = 5 cm).
Concept: A proof of the Pythagorean theorem by rearranging triangles
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In one sentence
The question this lesson answers
This is a right triangle: one of its angles is a right angle, 90 degrees.
The two shorter sides are the legs, a and b. The longest side, opposite the right angle, is the hypotenuse, c.
Transcript
What the lesson says
This is a right triangle: one of its angles is a right angle, 90 degrees.
The two shorter sides are the legs, a and b. The longest side, opposite the right angle, is the hypotenuse, c.
In our example, a is 3 centimetres and b is 4 centimetres.
The Pythagorean theorem says that in a right triangle, a squared plus b squared equals c squared, where a squared means a times a.
Why is it true? Put four copies of the triangle in the corners of a big square.
Each side of the big square is a plus b: 3 plus 4, or 7 centimetres.
The gap in the middle has four sides of length c and four right angles: a square with area c squared.
With our numbers, the big square is 7 times 7, or 49 square centimetres.
Each triangle has area 3 times 4, divided by 2, or 6. All four cover 4 times 6, or 24.
So the gap, c squared, is 49 minus 24, or 25 square centimetres.
Now slide three of the triangles to new places, without turning them.
Now the gap is two squares, one with side a and one with side b.
Their areas are a squared, 3 times 3, or 9, and b squared, 4 times 4, or 16: 25 in total, the same as before.
The big square and the four triangles did not change, so the gap has the same area both ways.
So a squared plus b squared equals c squared. Since 5 times 5 is 25, c is 5 centimetres.
Recap: moving the same triangles turns a gap of c squared into a squared plus b squared, so the two are equal.
Curriculum
Where this fits
- British Columbia, Grade 8
Mathematics, Geometry and measurement: Pythagorean theoremBC8-MA-31
Previous: The Pythagorean Theorem: Squares on the Sides of a Right TriangleNext: Finding the Hypotenuse with the Pythagorean Theorem
- British Columbia, Grade 11
History of Mathematics 11, Geometry: of lines, angles, trianglesBC11-MA-52
This lesson is also listed in Grade 11.
The outcomes and strands follow the British Columbia curriculum.
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