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Lesson · Grade 5 · Mathematics

Dividing with a Remainder: 157 ÷ 4

  • Grade 5
  • Mathematics
  • 1 min 7 s
  • British Columbia
  • BC5-MA-14

The video works out 157 ÷ 4 one step at a time from the left on a division frame. It starts with 15 (3 × 4 = 12, leaving 3), brings down the 7 to make 37 (9 × 4 = 36, leaving 1), and shows that the 1 left over is less than 4, so it is the remainder. It gives the answer 39 R 1, checks it with 39 × 4 = 156 and 156 + 1 = 157, and ends on the recap that what is left over at the end is the remainder.

Concept: Dividing with a remainder

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In one sentence

The question this lesson answers

What is 157 divided by 4?

We divide from the left, one step at a time.

Transcript

What the lesson says

What is 157 divided by 4?

We divide from the left, one step at a time.

1 is less than 4, so we start with 15.

4 goes into 15 three times, because 3 times 4 is 12.

15 take away 12 leaves 3.

Bring down the 7 to make 37.

4 goes into 37 nine times, because 9 times 4 is 36.

37 take away 36 leaves 1.

1 is less than 4, so it is the remainder.

So 157 divided by 4 is 39, remainder 1.

Check: 39 times 4 is 156.

Add the remainder: 156 plus 1 is 157.

What is left over at the end is the remainder.

Curriculum

Where this fits

British Columbia, Grade 5

Mathematics, Number: multiplication and division to three digits, including division with remaindersBC5-MA-14

Previous: Multiplying with an area model: 23 × 14Next: What a Remainder Means in a Word Problem

The outcomes and strands follow the British Columbia curriculum.

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