Grade 6, Measurement and geometry
Area of parallelograms
Find the area of parallelograms as base times height, or find a missing base or height.
Three levels
One skill, rising difficulty
Each sheet carries one level. The three are the same skill at rising difficulty, each named for what it practises.
- Level 1: Base and height to 10
- Find the area of each parallelogram.
- Level 2: Base or height above 10
- Find the area of each parallelogram.
- Level 3: Find the missing base or height
- Use the area to find the missing base or height of each parallelogram.
Worked example
How the sheet explains it
The helper printed at the top of each sheet: one solved example and the steps a student follows, before the first question. Every number sentence in it is proven by the same checker as the answer key.
Level 1: Base and height to 10
- A parallelogram can be cut and moved to make a rectangle with the same base and height.
- Area = base × height. Use the height that makes a square corner, not the slanted side.
- Area = 8 × 7 = 56 cm².
Level 2: Base or height above 10
- Area of a parallelogram = base × height.
- Split 16 into 10 and 6: 10 × 12 = 120 and 6 × 12 = 72.
- Add the parts: 120 + 72 = 192. Area = 16 × 12 = 192 cm².
Level 3: Find the missing base or height
Area = 72 cm² Base = 9 cm Height = 8 cm
- Area = base × height, so divide the area by the measure you know.
- 72 ÷ 8 = 9, so the base is 9 cm.
- Check: 9 × 8 = 72 cm².
Goes with
Reference sheets
One-page helpers a student keeps beside this sheet:
- Perimeter and area
- Formulas to remember
Every reference, facts and support sheet is listed in the worksheet catalogue.
In the BC curriculum
Content standards
The British Columbia content standard this skill is written for, by the codes used across this site:
- bc.math.6.c.12
The wording of each standard is on the Province's mathematics curriculum page.
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